The $e\psilon-\delta$ definition states that the limit of $f(x) = L$ as $x$ approaches $a$ if for all $\epsilon > 0$, there exists a $\delta > 0$, such that if $|x-a| < \delta$, then $|f(x) - L| < \epsilon$. The applet below courtesy of Sylvain Berube, shows its geometric interpretation.
Sunday, February 27, 2011
Friday, February 25, 2011
Instruction: Type the Equation a function in the text box and click the Graph button to graph the function. The step by step in creating this applet can be viewed here.
Wednesday, February 23, 2011
- ABCD' is a square. What shape is IJKL? Justify your answer.
- What is the relationship between the area of ABCD' and IJKL?
- Move slider α to the extreme right to verify your answer.